2.1 Models of hydrocarbons
2.2 Investigating properties and bonding of organic homologous series
2.3 Shapes of organic molecules
2.4 Properties and bonding of organic homologous series
2.5 Safety and organic substances
2.6 Hydrocarbons from the Earth – Implications
2.1 construct models, identify the functional group, and write structural and molecular formulae for homologous series of organic chemical compounds, up to C8
– alkanes
– alkenes
– alkynes
Homologous series are groups of compounds which are characterised by:
a common general formula
a common functional group
similar structures and chemical properties
gradations in their physical properties (as MM increases)
Task 2.1.1
1. Use the interactive to
a) model the homologous series https://chemagic.org/molecules/amini.html
b) write names and draw formulas
2. Write the molecular formula and draw the structural formula for the following alkanes:
a) methylbutane
b) 2,3-dimethylhexane
c) cyclopentane
3. Write the molecular formula and draw the structural formula for the following alkenes:
a) methylbut-1-ene
b) 2,3-dimethylhex-3-ene
c) cyclohepta-1,2-diene
4. Write the molecular formula and draw the structural formula for the following alkynes:
a) methylbut-1-yne
b) 2,3-dimethylhex-1-yne
c) cyclooctyne
2.3 analyse the shape of molecules formed between carbon atoms when a single, double or triple bond is formed between them
The shape of the distribution of atoms around any carbon atom usually this will fit one of three types:
Hybridisation (in valence bond theory, a procedure where atomic orbitals are combined to produce molecular orbitals) will have an effect on the molecular geometry.
Example 1: methane
If one of the electrons in the 2s orbital jumps to a 2p orbital, the excited carbon atom can hybridise this state to form 4 identical hybrid orbitals which are equivalent in energy, size and shape.
The formation of these hybrid orbitals slightly lowers the energy giving some added stability. The orbitals are arranged in an overlapping organisation which accounts for the tetrahedral arrangement of hydrogen atoms around a central carbon atom.
The single bonds representing the four sp3 hybrid orbitals are called sigma (σ) bonds. The sigma bond forms when the heads of two atomic or molecular orbitals overlap. As a result “you can have a sigma bond between an sp3 orbital on a carbon atom and a 1s orbital on a neighbouring hydrogen atom as well as from the overlap of two sp3 orbitals between neighbouring C atoms”. (Walker, 2019)
“A sigma bond is a covalent bond formed by overlap of atomic orbitals and/or hybrid orbitals along the bond axis (i.e., along a line connecting the two bonded atoms)”. (Walker, 2019)
We often draw methane as four bonds at right angles, but the molecular shape is actually tetrahedral. Another way of drawing this is:
Example 2: ethane
WHAT HAPPENS IN DOUBLE AND TRIPLE BONDS?
Example 3: ethene
Example 4: HCN (same shape as for ethyne)
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TASK 2.3.1
Select the true statement concerning bonding in hydrocarbon molecules: (Thickett, 2018, p. 133)
A) Carbon-carbon single bonds are formed when 4 electrons are shared
B) Double covalent bonds between carbon atoms consist of one electron pair
C) Triple covalent bonds between carbon atoms in alkynes consist of three electron pairs
D) C-H bonds are formed when sp3 hybrid orbitals from each atom interact.
2. The structure of hydrocarbons is heavily dependent on the bonding within and between the carbon backbone.
a) Identify the functional group of the linear hydrocarbon with the chemical formula C4H6. Include a structural formula in your answer (2 marks)
b) Describe the different geometries around each carbon from the structural formula in part a). (Shenfield & Silove, 2018, p. 73)
2.2 conduct an investigation to compare the properties of organic chemical compounds within a homologous series and explain these differences in terms of bonding.
When studying the properties of the hydrocarbons, there are two groups of properties that are important: physical properties and chemical properties.
Chemical properties
In very broad terms, the chemical properties of a compound or a series of compounds are associated with the intramolecular bonding (bonding between atoms in the molecule). Alkanes are characterised by single carbon-carbon and carbon-hydrogen bonds. The paired electrons are arranged in a tetrahedral arrangement and this gives a level of stability to the compounds, especially since the electronegativity values for both carbon and hydrogen are very similar, and so the covalent bonds (and therefore the molecules) are non-polar.
Chemical properties relate to the functional group
Both alkenes and alkynes are chemically more reactive than alkanes due to the presence of a double or triple bond.
Physical properties
The physical properties of the alkanes are related to the intermolecular forces between molecules. As a result the physical properties are not just based on the non-polarity of the covalent bonds within the molecules, but also on their size and shape. The dominant intermolecular bonds are dispersion forces.
The presence of non-polar bonds and non-polar molecules affects the physical properties of the compound. The hydrocarbons are separate (=discrete) molecules with strong covalent bonds in the molecule but only weak dispersion forces between molecules. As the chain length increases, the number of dispersion forces between molecules increases, and hence larger molecules have higher melting and boiling points: small alkanes exist as a gas at SLC (Standard Laboratory Conditions = 25C and 100kPa), butane, octane and several others are liquids, while the longer chains, such as the paraffin waxes (20+ carbon atoms) are solids.
The non-polar nature of the hydrocarbon molecules also makes them insoluble in a polar substance such as water. However as our rule is like dissolves like, they will dissolve in other non-polar solvents, eg CCl4.
The lack of free-moving electrons also means the hydrocarbons are poor electrical conductors.
Investigation 2.2.1
2. On one graph, plot the information from Table 10.1for boiling points for alkanes, alkenes, alkynes
3. Using DDL, explain the graphs in terms of number of carbons in the series for state at room temperature
4. From the data in the second table below
a) use DDL to explain the change in enthalpy of combustion for methane to hexane
b) predict whether the complementary alkene/alkyne would have a lower or higher enthalpy. Justify your answer.
Investigation 2.2.2 Experiment: Properties of Hydrocarbons
Introduction
Hydrocarbons are compounds which contain only carbon and hydrogen. They can be classified into several types, depending on their structure.
Chain hydrocarbons are divided into three classes:
In this experiment you will perform experiments to illustrate some of the properties of saturated and unsaturated hydrocarbons.
Method
Solubility and Density of Hydrocarbons
1.Collect a 5mL sample of each of the following hydrocarbons; hexane (H-), hex-1-ene (H-e), cyclohexane (CH), cyclohexene (CH-e).
2. Collect four test tubes and place them in a test tube rack. Label the test tubes H-, H-e, CH, CH-e.
3. Add 5 mL of water to each test tube.
4. Test the solubility of the four hydrocarbons in water by adding 1mL of one hydrocarbon with a dropper to the 5mL of water in the test tube marked with its identifier (ie, add 1mL of hexane to the test tube of water marked H-).
5. Repeat step 4 for each hydrocarbon.
6. Look for the formation of any separate layers and determine which is the water layer in each case.
7. Collect another four test tubes and place them in a separate test tube rack. Label the test tubes as before.
8. Add 5 mL of dichloromethane to each test tube.
9. Test the solubility of the four hydrocarbons in dichloromethane by adding 1mL of one hydrocarbon with a dropper to the 5mL of water in the test tube marked with its identifier (ie, add 1mL of hexane to the test tube of water marked H-).
10. Repeat step 8 for each hydrocarbon.
11. Test the solubility of the four hydrocarbons in dichloromethane. If separate layersare formed, determine which is dichloromethane in each case.
12. Record your results.
2.4 explain the properties within and between the homologous series of alkanes with reference to the intermolecular and intramolecular bonding present
First, a review of intermolecular forces (attractions) as opposed to intra-molecular bonding.
Van der Waals forces is a general term used to define the attraction of intermolecular forces between molecules. There are two kinds of Van der Waals forces
The chance that an electron of an atom is in a certain area in the electron cloud at a specific time is called the "electron charge density." Since they do not all stay in the same area 100 percent of the time, if the electrons all go to the same area at once, a dipole is formed momentarily. Even if a molecule is non-polar, this displacement of electrons causes a non-polar molecule to become polar for a moment.
Since the molecule is momentarily polar, where the electrons are concentrated at one end, the molecule is partially negatively charged on that end. This negative end makes the surrounding molecules have an instantaneous dipole also, repelling the neighbouring molecules' electrons and attracting the surrounding molecules' positive ends. This process is known as the London Dispersion force of attraction.
When the molecules become temporarily polar, the melting and boiling points are raised because it takes more heat and energy to break these bonds. Therefore, the greater the mass, the more electrons present, and the more electrons present, the higher the melting and boiling points of these substances.
These forces occur in molecules that are permanently polar versus momentarily polar. In this type of inter-molecular interaction, a polar molecule such as water or H2O attracts the positive end of another polar molecule with its negative end of its dipole. The attraction between these two molecules is the stronger dipole-dipole force.
A hydrogen bond is a special type of dipole-dipole attraction which occurs when a hydrogen atom bonded to a strongly electronegative atom is close to another electronegative atom with a non-bonding pair of electrons.
These bonds are generally stronger than ordinary dipole-dipole and dispersion forces, but weaker than true covalent andionic bonds.
For a hydrogen bond to occur there must be a hydrogen atom covalently bonded covalently bonded with a strongly electronegative atom such as N, O, or F. The electronegative ion or molecule must posses a non-bonding electron pair (O has two in water, shown as twin sets of dots in the diagram below left) in order to form a hydrogen bond.
Since the N, O or F atom is strongly electronegative, it pulls the covalently bonded electron pair closer to its nucleus, and away from the hydrogen atom. The hydrogen atom is then left with a partial positive charge, creating a strong dipole-dipole attraction (shown as dotted lines in the diagrams below) between the hydrogen atom bonded to the donor, and the non-bonding electron pair on the electronegative atom.
Note: Chlorine has a relatively low ability to form hydrogen bonds because it is a large atom. When the radii of two atoms differ greatly in size or are both large, their nuclei cannot get close enough when they interact, so they have only a weak interaction.
Start at the green box on the left halfway down.
Note: We just call "London dispersion forces" dispersion forces
No need to learn detail. This is to give you an idea of the energy required to overcome the attraction and move it to a freer state (ie solid to liquid or liquid to gas).
Important for us are:
There is a direct relationship between the number of carbons in an alkane and its melting/boiling point temperature.
The higher the number of carbons, the higher the temperature. For boiling point, this is a direct result of increased intermolecular (van der Waals) forces that are present in a larger molecule - a consequence of the increased surface area of a large molecule, which provides greater possibility for interaction between molecules.
Looking at the graph above, there is a clear trend of increasing boiling point.
The trend line is almost perfectly linear. It suggests a strong relationship between boiling point and molar mass for alkanes. The difference between each member of the alkanes is the addition of a CH2 group. This additional group increases the size of the molecule and also increases the strength of the dispersion forces between the molecule. These are the forces which must be overcome for the molecules in a liquid to be free as gas molecules.
One other factor which can affect the physical properties is the shape of the molecule.
Pentane, methyl butane and dimethyl propane all have the same molecular formula and hence the same molar mass (72.146 g/mol) however, the boiling points are as follows:
Pentane 36oC
Methyl butane (isopentane) 27.8oC
Dimethyl propane (neopentane) 10oC
As the compound becomes more branched, the available surface area is less, the dispersion forces holding the molecules together become slightly weaker, and so the highest melting point is for the most linear compound (pentane).
Dispersion forces are stronger in long chains of compounds.
Solubility is another physical property affected by intermolecular forces.
Consider the table below of solubility of alcohols in water (polar) or hexane (non-polar) solvents
The term miscibility refers to the ability of a liquid solute to dissolve in a liquid solvent.
Solubility is more often used to mean the ability of a solid solute to dissolve in a liquid solvent. Miscibility is used when talking about the solubility of -- specifically -- liquid solutes.
Miscible liquids are also defined as liquids that can mix to form a homogeneous solution. Miscible liquids generally mix without limit, meaning they are soluble at all amounts.
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THINKING POINT:
What effect does the hydroxyl (-OH) group of an alcohol have on its melting and boiling point? Predict whether the boiling point will be higher for a non-branched alkane of the same C number.
Extra reading
TASK 2.2.1 Research to understand the answers to the following questions.
1. In general, the alkene homologous series with increasing number of carbons show little variation in what? (Shenfield & Silove, 2018, p. 72)
A) Freezing point
B) Strength of inter-molecular forces
C) Density at room temperature
D) Flammability
2. Alkanes are generally unreactive species. This can be explained by which of the following? (Shenfield & Silove, 2018, p. 72)
A) Consist only of highly stable carbon-carbon bonds
B) Lack of functional groups
C) Highly non-polar nature
D) Relatively low boiling points
TASK 2.2.2 Use the scaffold to answer the question
This has errors, eg last box should be alcohols not alkenes.
2.5 describe the procedures required to safely handle and dispose of organic substances
THIS IS REQUIRED ROTE LEARNING:
The most critical aspect to the safe handling of hydrocarbons is their flammability. Most hydrocarbons easily combust and so must be kept well away from a naked flame.
The alkanes from methane to octane are gases or volatile liquids at SLC and have low flash points.
Petrol is a mixture of hydrocarbons and other components which lower its flash point and make it potentially dangerous to store and use. There are warnings in petrol stations regarding smoking and the use of mobile phones to ensure there is no opportunity to ignite the volatile liquid.
Weak dispersion forces between the smaller alkanes lowers their boiling points and increases their volatility. They have low flash points (see definition below) and can be readily ignited even during the lower temperatures in winter.
Volatility is a term used to describe substances which vapourise at room temperature to produce a high vapour concentration above the solid or liquid phase. This high concentration is known as the ‘equilibrium vapour pressure’.
Some hydrocarbons vapourise readily at standard laboratory conditions. In general, the lower the molecular weight, the greater the rate of evaporation and the higher the volatility, due to weaker dispersion forces between molecules.
Boiling point is a good indicator of volatility. Volatility increases with increasing temperature.
Flash Point is a term used to describe the minimum temperature at which the vapour pressure of a hydrocarbon is sufficient to combust in air. Combustible fuel-air mixtures can be dangerous because a spark or flame can ignite them. Flash points can vary, but generally the higher the boiling point of a hydrocarbon, the higher its flash point.
Solid waxes have higher boiling points and flash points than liquid hydrocarbons because stronger dispersion forces makes them less volatile. This lowers the vapour pressure and raises the flash point.
Liquids like octane have weaker dispersion forces between the molecules and are more volatile with lower flash points. This makes them potentially dangerous to store and use.
Safety Precautions:
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TASK 2.5.1
1. Explain the terms ‘flash point’, ‘ignition temperature’ and ‘vapour pressure’ and why they are relevant when discussing safety in relation to handling of hydrocarbons. (3 marks)
2. Look at the two RiskAssess labels above. Evaluate the choice of cyclohexane as a safer option over hexane for experiments involving hydrocarbons. (3 marks)
3. What is the safest way to dispose of hydrocarbons once you have concluded your experiments? Justify your response (2 marks)
4. Explain why each of the following safety precautions is taken when handling or storing hydrocarbon fuels:
a) LPG gas bottles should be inspected and tested regularly
b) Lawn mower fuel should be poured into the mower’s fuel tank out in the open.
c) The use of mobile phones is not permitted around petrol stations.
d) Large quantities of petrol should not be stored at home.
e) Petrol tankers are grounded through attachment to steel chains.
f) The petrol tank in a car is usually at the opposite end to the engine.
2.6 examine the environmental, economic and sociocultural implications of obtaining and using hydrocarbons from the Earth
Hydrocarbons are commonly found in high concentrations in fossil fuels. Two of the simplest hydrocarbons are methane and ethane, the primary components of natural gas.
Petroleum is a critical commodity in the modern world. What sorts of compounds can be obtained from a barrel of crude oil? How are they obtained?
ENVIRONMENTAL:
Obtaining petroleum and natural gas from the Earth involves drilling through rocks deep in the Earth’s crust. Hydrocarbons from the drill machine’s lubricants can be dispersed into surrounding water polluting the surrounding seawater or ocean. These hydrocarbons are toxic to aquatic organisms that reside in the sea.
These rocks, which often contain barium ions from the traces of lubricant that remain, are also returned into the ocean. These barium ions interfere with enzyme activities, which can result in death of living organisms.
Potassium ions in the machine lubricants in extracting the hydrocarbons can result in uncontrollable algae growth, leading to eutrophication. This allows algae to grow on the water surface, blocking the sunlight reaching to the plants beneath the water as well as oxygen gas that is dissolved in the water. This can result in the death of plants, which decreases the oxygen availability in the water for aquatic animals like fish, as well as bacteria that further use more oxygen to decompose dead plants. It destroys the aquatic ecosystem, turning a habitable environment into a toxic one for the original species.
Another environmental implication would involve the noise pollution through the sending of sound waves to detect potential hydrocarbon deposits for drilling. This would disturb local aquatic organisms, such as whales, as well as any humans that are near the area. The sound waves can disorientate whales, resulting in large scale whale stranding on beaches and can cause death.
Hydrocarbons must be transported by ship from the sea to land to oil refinery so that petroleum can be split into components. Oil spillages have also caused environmental damage similar to those already mentioned, but hydrocarbons can be washed ashore polluting beaches.
Using:
Hydrocarbons that enter the human body could cause severe respiratory irritation. The long term effects of hydrocarbon exposure is also currently not fully understood.
Along with the expansion of the petrochemical industry from energy generation to polymer production and the associated economic benefits of both industries, environmental considerations have become more critical, especially as scientists link climate change to our reliance on the burning of fossil fuels. This has spawned new industries devoted to greener energy production and investigations into alternate fuel sources which might reduce the impact on the environment.
Economic:
Potential implications such as leaking toxic hydrocarbons, potassium ions and eutrophication discussed earlier could all result in the death and reduction in biodiversity of aquatic organisms. It is important to preserve biodiversity as aquatic organisms serve as a major source of economic revenue in many countries.
The world's reliance on a small number of sources of petroleum puts their financial viability at risk should there be shortages from natural causes, embargoes or war.
Sociocultural:
Workers involved in the drilling process to obtain hydrocarbons will be exposed to drilled rocks that are covered in toxic hydrocarbon lubricants, as well as the lubricants in the machinery itself, which can be accidentally or voluntarily inhaled as oil mists in the air.
The leaking of toxic hydrocarbons, potassium ions and eutrophication during the extraction of hydrocarbons can result in a decline in biodiversity of aquatic organisms. This has implications in removing or limiting the range of available food which humans can enjoy. As the supply of aquatic organisms decreases due to hydrocarbon pollution, the price of seafood would increase, it would be less affordable for the global population in general.
The presence of toxic hydrocarbons would result in our everyday potable (drinkable) water derived from the sea being toxic. The treatment of water would need to be more extensive, which would incur additional cost to consumers.
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TASK 2.6.1
1. (2006, Q1)
Which is the main industrial source of ethylene?
A) Ethanol
B) Glucose
C) Petroleum
D) Polyethylene
2. The process of fractional distillation is used to separate crude oil into different fractions. One of the compounds obtained from fractional distillation is C10H22. This compound undergoes catalytic cracking as follows: (08, Q16, 5 marks) (modified).
C10H22 → C8H18 + X
a) Identify X.
b) What is the functional group for X?
c) To which homologous series does C8H18 belong?
3. Carry out some research to complete a table: environmental, economic and sociocultural implications of obtaining and using hydrocarbons from the Earth